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(1 point 16 18 I W AB has length 18 and AC has length 16, find: • The length of MC . The measure of angle B in degrees): . Th
in paino 15 9 14 AB has length 9 and BC has length 15, find: • The length of AC: • The measure of angle B in degrees • The me
My blackboard Com Practice Question or Previous problem Problem List Next Problem in point 19.1 A 3.7 B If AB has length 3.7
11 A HAC has length 5 and HC has length 11, find • The length of AB: . The measure of angle B in degrees . The measure of ang
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Answer #1

1) Length of BC :

BC2 = AC2 + AB2

BC2 = (16)2 + (18)2

BC2 = 256 + 324 = 580

BC = sqrt(580) = 24.083

Hence, length of BC = 24.083

Now, angle B:

tan \theta = 16 / 18 = 8 / 9

\theta = tan-1(8/9) = 41.633 degrees

Measure of angle B is 41.633. degrees

Now, measure of angle C = 90 - 41.633 = 48.367.degrees

2) Length of AC:

BC2 = AC2 + AB2

(15)2 = AC2 + (9)2

225 - 81 = AC2

AC = sqrt(144)

AC = 12

Now, measure of angle B:

tan \theta = 12 / 9 = 3 / 4

tan \theta = 0.75

\theta = tan-1(0.75) = 36.869 degree

Measure of angle B is 36.869 degrees.

Now, measure of angle C is ( 90 - 36.869 ) = 53.131 degrees

3) Length of AC:

BC2 = AC2 + AB2

(19.1)2 = AC2 + (3.7)2

364.81 - 13.69 = AC2

AC2 = 351.12

AC = sqrt (351.12) = 18.738

Now, the measure of angle B:

tan \theta = 18.738 / 3.7 = 5.064

\theta = tan-1(5.064) = 78.830 degrees.

So, measure of angle B is 78.830 degrees.

Also, the measure of angle C is (90 - 78.830) =11.171 degrees.

4) Length of AB:

BC2 = AC2 + AB2

(11)2 = (5)2 + AB2

121 - 25 = AB2

AB = sqrt(96) = 9.797

Now, measure of angle B :

tan \theta = 5 / 9.757 = 0.5124

\theta = tan-1 ( 5 / 9.757 )

\theta = 27.130 degrees.

Now, the other angle 90 - 27.130 = 62.face rhaping

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