Question

Using images 6.6 – 6.8, determine the amplitude of the calibration waveform. Be sure to include proper units:

[Image 6.6 – Calibration Waveform Display]

100- 90 08

[Image 6.7 – Calibration Waveform Vertical (VOLT/DIV) Setting]

[Image 6.8 – Calibration Waveform Horizontal (TIME/DIV) Setting]

# of vertical divisions
VOLT/DIV
Amplitude

Determine the period and calculate the frequency:

# of horizontal divisions
TIME/DIV
Period
Frequency

The calibration waveform has a specified amplitude of 2.0 V_PP at a frequency of 1.0 Khz. How accurate is the oscilloscope’s vertical calibration in % error?

% Error

How accurate is the oscilloscope’s horizontal calibration in % error?

% Error

Answer 1

0 Given, 2 volt y = VPL = 2 2 = 1 volt f = 1KH2 =103 Hz : The peak value measured from the oscilloscope at 103 HZ frequency is given by Vpim 5.25 X 5x103 5x10-3 = 1.05 voll y. error 1.05 X 100 1 = 9 y. The oscilloscope's vertical callibration is 95./ accurate-inst The time period of callibration, T = \ - 1533 period from mea mesurement. Tm= 5x10 3 The time at an AL 2 S The time period at- Bu hits Hy frequency is Tm SX 103 X 1 = 9.52x101 5.25 error 11 103 9.52x109/ x 100% 10- 3 4.764 The oscilloscope's horizontal cat callibration is 95.24 % accurate.
Thanks