Question

Let А and B be similar nxn matrices. That is, we can write A = CBC- for some invertible matrix с Then the matrices A and B ha
A. Both А and B have the same characteristic polynomial. B. Since A = CBC-1 , this implies A = CC-B = IB = B and the matrices
with corresponding eigenvector ū . Then we have the following. AT = CB (0-10) = CB(20) = 10C (BŪ) = 10c (av) = 110(C) = 1 (

It follows that 2 is also an eigenvector of the matrix А D. All of the above. E. Both A and C. O A B. C. OD. O E.
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Answer #1

Page 1 (B) Commutative property does not hold for product of two matrices CBCT & CCIB. . Option (B) is incorrect Optionc isSolution : - such that an invertible matic c A=(TBC LA. Since A and B are similar, there existe PA(A) and P. (A) cenote the c

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