Question

Q2: (50%) Design negative moment for the maximum and maximum shear of a continouse one-way solid slab supported on beams spaced at 14 ft on centers. The width of the beam is 12 in. The uniform dead lood of 120 psf (including self weight of slab) and live read of use ACI 318 code moment and shear coeffocents for continouse beams und slab. Pc = Hksi, for boksi, h=6in, d= 5:06 in, try #3 bals. slab carries a 100 psf.

Answer 1

Solution:- Q2 o beam = 14" 12" Width clear 14-1 = 13" Given that, Center to center spacing of beam spaling Ln Loading : 120 psf Lave load 100 psf consider unit width slab, b = 16+ 120 plf WALL Dead toad of INDL 120 * 1 = 100*1 10001 ASCEILRED fasaud load: Wu =1.2* WOL + 1-6* WILL = 1*2*120 + 1.6 * 100 3ouplf =0.304 kelft. Manimum negative "mement MD = 0- 304 *13 2 10 = 5.1376k- Marnimum negative shear Vu = 1-15* 0-304* LE 12 = 2.272k1pS use ACL 318 code moment and shear coefficiente for continuous beams and slab. 6.5 (ACI 318) simpleſsed method of analysis 18? non- purestined continuous leans and one evay sold slabe negative moment coefficient

At Interior face of Exterior support support as spandrel beam 1/24 A other faces of interior supports allu At Exteriše face of first interior support - 10 henee, monimum moment will be at enterio face of fizist interior support Moment coepfferent = WU *in 2 Wy* ln 10 In 28 the clear span *Shanno coellicient 6.5-4 due to gravity loads Enterior face of first interior support 1015 * lut in frace of all other supports wu * Lon/z Marlimum negative shear 1.15* Wu* in 2 2