Question

Show Mass Labels O Forces from Objects O Level Position None O Rulers O Marks Bricks 5 kg 10 kg 0.25 0.5 0.75 1 1.25 1.5 1.75 2 Meters 15 kg 20 kg 2 1.75 1.5 1.25 1 0.75 0,5 0.25 Meters Place a 10-kg brick at the 1.75-m mark on the left and a 5-kg brick at the 0.5-m mark on the right. What do you need to place on the right to balance the beam? Calculate the CW and CCW torque and see which side needs a boost. CW Torque: CCW Torque: Which torque is less in magnitude? This is the side where you need to place load for additional torque. Balance the Beam: Experiment with bricks and positions to balance the beam. What mass did you use? At what location? Compare the CW and CCW torque again. Total CW Torque: Total CCW Torque: Are they equal in magnitude?

Answer 1

Soln INITIAL ch Torque 5 kg 2 T Fort lokg 0.5 5810 X 0.5 A Ac Tcual : 25 Nimi 2 1075 CCNL Torque Сcc lal . 10 X 10 X 1.575 -175 Nim less in mag ni 'tude nite Cin Torque is (175 - 25) -150 Nm. e he LLS e he put 15 Kg brick. kg brick at from pivot right the 15 at distance 1m on t side. FINAL Total cu Torque- Tche- 5 X10 X 0.5 + 15 xlox Tcula 25 +150 N. - Total ceul Torque sat coulin cs Catheyner are equal in Toxlox1.75 175 N·m mag nitude.