Question

[6]29. The figure represents a solid sphere, radius of 5.62 cm, concentric with a spherical shell of radius 7.90 cm. The inner sphere has a charge of +(5.6 x 108)e on it and the outer shell has a net charge of -(5.6 x 108)e on it. Determine the electric field at 6.00 cm from the center. Answer: Magnitude: Direction: 9.4 cm [8]33. The magnetic field through the rectangular loop shown in the 5.6 cm figure changes according to the relation B(t) = (3200 - 15.1t2) T with t in seconds. The resistance of the loop is 15.2 m 2. B Based on the above information circle the statement(s) that is (are) TRUE. Statements: (a) At t= 2.8 s the magnetic flux is decreasing. (b) At t= 2.8 s the magnetic flux is increasing. (c) Att=2.8 s the induced current lind in the rectangular loop is non zero and is clockwise. (d) Att = 2.8 s the induced current iind in the rectangular loop is non zero and is counterclockwise. (e) This problem is based on Faraday's law.

Answer 1

The solution is given below.

29. Spherical Gaussions surface of radius 6.00 un concentric Construct with the solid sprere. froom Gauss law Sed Q enclosed Eo Penelosed - charge enclosed by Gaussian surface = 56*100 . E sds 8 8 5.6410° e Eo 5.6x108 e € 49 R² = - 19 e = 1.6810 | 9x109 2 UITE Nm 62 5.64 108 1.6x1019 GITE R² 5.6x108x16x10' xgx10 010872 R = 6:00 am -19 0:06 m 224 N/ Answer Magnitude 224 / Direction: outward from the center The problem is based on Faraday's law 3200 - 15.1t 33. Area of Loop = A=5.689.4 can flux ☆ BA 3200 A - 15.1 At² Now change dt - 15:18A-27 =- 30.2 At i at t= 2.85 in flux d& indicates negative siger the flux is decreasing, the magnetic flaxis decreasing, empa do Now indneed 30.2 At indneed current zind emf resistance - 30.2 At 15.2 MA Fo att-2.8 induced current at Answer. t = 2.8s is non zero and is counterclockwise (a) at t= 2.8s the magnetic fluxis decreasing (d) at t= 2.85 the induced current ind in the rectangular Loop is and counter clockwise (e) The problem is based on faraday's law. non zero

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