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A cannon launches a cannonball 20 degree above the horizontal off of a 75-meter high cliff...

A cannon launches a cannonball 20 degree above the horizontal off of a 75-meter high cliff
The initial speed of the cannonball as it leaves the cannon is v0=50m/s.
what maximum height above the bottom of the cliff does the cannonball reach?
find the velocity of the cannonball exactly 2 seconds after it fired

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Answer #1

10-somis 32= 20 h=75 e(s) m a Voor o = so Ces 20° - 46.98 mis Icy) maximum height = ht vo zsin 20 2g 75 + (502x sim zoo 2x9.8

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