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Verify Kirchhoff's Voltage Law using loops Table 2 From Circuit 2: Table 2 R (92) 560012 330092 180002 Experimental results I(A) 0.016A 0.010A 0.006A V (volt) 88.63V 313300 12 1800 22 5600 22 Loop 1 Loop 2 120.0 V 100.0 V Current 0.010 A Current 0.016 A Current 0.006 A

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Answer #1

Using krickhoffs law In outer loop (1000 x 0.006) 0.006) +100 (5200 X0.016) co 10.8 + 89.6 = 100 100. un 100 iv In left loop

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