Question

IIULILIP UILD A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0x106 N/m2. If this piece of abductin is 4.0 mm thick and has cross-sectional area of 0.50 cm?, how much potential energy does it store when compressed 1.0 mm? (Hint: Young's modulus of elastic and Hooke's law )

Answer 1

Son Here it is given that * Young's modulus is Y = = 20x100 N/m² D = 4.0mm 4X10-3 m thickness is ☆ Area = 0.50 m2 0.50 x 10-4 m2 compress of the pipe x = 10mm = 1x10 -3 m. Treating the abduction as a spring let us find k by K = Stress Area thickness Y X Area thickness (2.0x106 N/m²)x(0.50X1542) 4 x 10-3 m 2.58104 Nim Now using the potential energy formula for spring Ź KX² u IX 2.5x104 x (1.0X10-3)? u = 2 1.25 x 10 -2 J Ans.