Question

Consider the circuit shown below. Find V, (in V), 12(in A), and I, (In A). (Due to the nature of this problem, do not use rounded intermediate values in your calculations- including answers submitted in WebAssign. For the currents, indicate the direction with the signs of your answers.) 1-9A 112 R, - 180 R, = 90 V = 42 R, -40 V А 1,- A

Answer 1

Given Circuit is: B Iz A 1,=3A fI2 ER₂=90 Ri=182 V2-421 + e @ Vi=?_ R3 =0 42 Vi = ? In = ? Iz = ? Abflying the Kirchoff's law at nogle B ( Jun chion law) a 611)+(-7)+ 13 0 the current entering the Jimction is taken -ve. the loop law in loop 0 I, RI+I₂ R2 =0 V = IIRI - I₂ R₂ = 9x18 - 1, x 9 And by loop law in loop ③ V₂ - I3 R3 - I2 R2 = 0 By 42 = Iz x4 + I2 x 9 or, from ean 0 so, I3 = Ist I put in 42 = 4(I t Iz) tot 42 = 4x9+ 412 + 9 Iz 13 I2 = 6 or I₂ = E SA

Put Iz in egn 0 -9-+13 =0 I3 = 123 А so Vi= 9x18 – 1, 49 V = 9x18 - XS V = 108. volt 13 Answers Vi= 8.307 alVi= 8,31 V I2 = 0,46A Is = 9,46