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Consider the circuit shown below. Find V (in V), 12 (in A), and 1z (in A). (Due to the nature of this problem, do not use rou

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8A Р Iz Apply KCL at Node p I 2 &r Ibr - 400 Iz = I2 +8 + Loop2 Loop I > 40 Apply kue in Loop I V, = 1 6x8 – 812 Vi= 128–812if you have any query please comment

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