A hydrogen atom has an excited electron in the n = 5 state. The electron descends...
When an excited electron in a hydrogen atom falls from n = 6 to n=2, a photon of violet light is emitted. If an excited electron in an Het ion falls from n = 5, which energy level must it fall to (nı) for violet light of a similar wavelength to be emitted? ni =
An electron in the Hydrogen atom is in the excited state with energy E2. a) According to the Bohr model, what is the radius of the atom in this state, in Angstroms? b) What is the wavelength le of the electron, in Angstroms? c) What is the momentum of the electron, in kg-m/s ? d) This atom decays from the excited state with energy E2 to the ground state with energy E1 . What is the energy of the emitted photon?...
An electron in an excited state of a hydrogen atom emits two photons in succession, the first at 2624 nm and the second at 97.20 nm, to return to the ground state (n=1). For a given transition, the wavelength of the emitted photon corresponds to the difference in energy between the two energy levels. What were the principal quantum numbers of the initial and intermediate excited states involved?
Electrons in an unknown atom(not hydrogen) are excited from the ground state to the n=3 energy level. As these electrons make quantum jumps back to the ground state, photons of three different energies are emitted. The most energetic photon has an associated wavelength of 62.2 nm and the least energetic photon has an associated wavelength of 207 nm. What is the associated wavelength of the other type pf photon? The answer is 3-1 (20 eV), 3-2 (6 eV) and 2-1...
6. [18 PTS] SPECTROSCOPY The electron in a hydrogen atom is in the n-5 state. a. Calculate the energy of the electron. b. Calculate the orbital radius of the electron according to the Bohr model. The electron drops down to the n 3 state. c. Calculate the energy of the emitted photon d. Calculate the wavelength of the emitted photon.
An electron in the hydrogen atom make a transition from the ground state to an excited level by absorbing energy from a photon. The wavelength of the photon is 95.0 nm. What is the final level that the electron can reach?
When an electron of an excited hydrogen atom descends, from an initial energy level (ni) to a lower (nf), characteristic electromagnetic radiation is emitted. The Bohr model of the H-atom allows the calculation of ?E for any pair of energy levels. ?E is related to the wavelength (?) of the radiation according to Einstein's equation ( ?E = [(hc)/?]). Distinct series of spectral lines have been classified according to nf: Lyman series:nf=1 (91<?<123 nm; near-UV). Balmer series:nf=2 (365<?<658 nm; visible)....
A highly excited atom of hydrogen makes a transition from the n = 11 to the n = 10 state and emits a photon. What is the energy of this photon in joules? What is the wavelength in meters of the photon emitted when this highly excited hydrogen atom of hydrogen makes its transition from the n = 11 to the n = 10 state?
9.6 A hydrogen atom in its ground state (n = 1) is excited to the n = 5 level by absorbing photons. It then makes a transition to the n = 3 level and then from n = 3 level directly to the ground level. (a) What is the wavelength of absorbed photon? (b) What are the wavelengths of the emitted photons? [Answer: (a) 95 nm, (b) 1282 nm and 103 nm] Please show work and explain how. I do...
A ground state hydrogen atom absorbs a photon of wavelength A. The atom's electron is excited to the orbital level n 6. What was the wavelength absorbed (in nm)?