Need helping figuring out part B of the problem.
for 95% CI; and 6 degree of freedom, value of t= | 2.447 | ||
therefore confidence interval=sample mean -/+ t*std error | |||
margin of errror =t*std error= | 2.7153 | ||
lower confidence limit = | 5.86 | ||
upper confidence limit = | 11.29 |
from above 95% confidence interval =(5.86 ,11.29)
(please try 5.85 ,11.28 if this comes wrong)
Need helping figuring out part B of the problem. A manufacturer produces both a deluxe and...
I ONLY NEED HELP WITH PART OF PART "B" I've figured out the test statistic is -1.73 and the degrees of freedom are 5. However, I'm having a hard time finding the P value via the chart (which I'm required to learn how to do).I think the chart immediately bellow this is the one used to find the p-value. However, I know at least one (or more) of the charts bellow is what's used. Please let me know which chart...
I ONLY NEED HELP WITH PART OF PART "B" I've figured out the test statistic is -1.73 and the degrees of freedom are 5. However, I'm having a hard time finding the P value via the chart (which I'm required to learn how to do).I think the chart immediately bellow this is the one used to find the p-value. However, I know at least one (or more) of the charts bellow is what's used. Please let me know which chart...