one way anova
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treatment | G1 | G2 | G3 | L4 | ||||
count, ni = | 5 | 5 | 5 | |||||
mean , x̅ i = | 25.400 | 28.80 | 27.20 | |||||
std. dev., si = | 2.4 | 1.3 | 1.3 | |||||
sample variances, si^2 = | 5.800 | 1.700 | 1.700 | |||||
total sum | 127 | 144 | 136 | 407 | (grand sum) | |||
grand mean , x̅̅ = | Σni*x̅i/Σni = | 27.13 | ||||||
( x̅ - x̅̅ )² | 3.004 | 2.778 | 0.004 | |||||
TOTAL | ||||||||
SS(between)= SSB = Σn( x̅ - x̅̅)² = | 15.022 | 13.889 | 0.022 | 28.93333333 | ||||
SS(within ) = SSW = Σ(n-1)s² = | 23.200 | 6.800 | 6.800 | 36.8000 |
no. of treatment , k = 3
df between = k-1 = 2
N = Σn = 15
df within = N-k = 12
mean square between groups , MSB = SSB/k-1 =
28.9333/2= 14.4667
mean square within groups , MSW = SSW/N-k =
36.8/12= 3.0667
F-stat = MSB/MSW = 14.4667/3.0667=
4.72
F-critical = 6.927
anova table | ||||||
SS | df | MS | F | p-value | F-critical | |
Between: | 28.9 | 2 | 14.5 | 4.7 | 0.031 | 6.927 |
Within: | 36.8 | 12 | 3.1 | |||
Total: | 65.7 | 14 | ||||
α = | 0.01 |
Decision: , do not reject null hypothesis
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eta square ,effect size = SSbet/SST= 0.44
mediumeffect
,,,,,,,,,,,,,,,,,,,,,,
TUKEY HSD/KRAMER | |
Level of significance | 0.01 |
no. of treatments,k | 3 |
DF error =N-k= | 12 |
MSE = | 3.0667 |
q-critical value(0.01,3,12)= | 5.0459 |
confidence interval | |||||||||
mean difference | absolute mean difference | critical value | lower limit | upper limit | result | ||||
µ1-µ2 | -3.40 | 3.40 | 3.95 | -7.35 | 0.55 | no, means are not different | |||
µ2-µ3 | 1.60 | 1.60 | 3.95 | -2.35 | 5.55 | no, means are not different |
.................
Please let me know in case of any doubt.
Thanks in advance!
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