3. A work of 50 ft-lb stretches a spring 10 inches beyond its natural length. How...
A force of 10 lb is required to hold a spring stretched 1/3ft beyond its natural length. Which of the following integrals represents the amount of work done in stretching it from its natural length to 1/2 ft beyond its natural length? 5/6 30x da J1/2 -1/2 30x da 0 so" [" -1/2 20. dac 1/2 10 zda 0 3 Com S 5/6 203 do 1/2
A force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching it from its natural length to 10 in. beyond its natural length?
if the work required to stretch a spring 2 feet beyond its natural length is 15 ft- Express the limit as a definite integral: 6 lim - n جn = 1+ ()4 6 da Jo =(1+24) 6 dz =(1+24) 6 dx 1 + r4 1 1+ 4 6 1 + 4 Question 3 w ity *
The work required to stretch a spring 1.2 meters beyond its natural length is 36 Joules. The force required to hold the spring at a length of 6 meters is 100 Newtons. Find the natural length of the spring.
Suppose that 6 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 34 cm. (a) How much work is needed to stretch the spring from 26 cm to 30 cm? (Round your answer to two decimal places.) J 1.52 (b) How far beyond its natural length will force of 40 N keep the spring stretched? (Round your answer one decimal place.) x cm 19.33 Suppose that 6 J of...
9. a. A spring has constant k-5lb./in. Its natural length is 12 inches. What is the work required to compress it to 9 inches? b. A 100 ft. cable weighs 40 lbs. Find the work done in winding the cable onto a winch, if the cable is hanging vertically c. An unknown positive charge q is placed at the origin. The force F (in Newtons) with which this charge repels a unit positive charge is given by F-kq/r, where k...
a 4.00 lb weight stretches a certain spring 0.500 ft. With this weight attached, the spring is pulled 3.00 inches longer than its equilibrium length and released. Find the equation of the resulting motion, assuming no damping. y=?
A spring has a rest length of 14 inches spring and a force of 5 pounds stretches the spring to a length of 22 inches force How much work is done stretching the spring from a length of 15 inches to a length of 23 inches? Represent the amount of WORK as an integral. b Work = وه Preview dx a inches b = inches Then evaluate the integral. Work = inch*pounds
Please show all work! Thank you! P.S. 5.2 Q2 A force of 15 lb stretches a spring 3 ft. A 8-lb weight is attached to the spring and the system is immersed in a medium that imparts a damping force equal to its instantaneous velocity. (a) Find the equation of motion if the weight is released from rest 15 inches above equilibrium position x(t) Preview (b) the weight is released 15 inches above the equilibrium position with an upward velocity...
714 Suppose that 6 ) of work is needed to stretch a spring from its natural length of 36 cm to a length of 51 cm. (a) How much work is needed to stretch the spring from 44 cm to 45 cm? (Round your answer to two decimal places.) X] (b) How far beyond its natural length will a force of 10 N keep the spring stretched? (Round your answer one decimal place.) 105.91 X cm Need Help? Read It...