Homework Answers
value of R4 = 200
Number of times Loop executes = 200/4 = 50
(a)size of 1 instruction = 4 bytes
size of memory needed = 9*4 = 36 bytes
(b)Number of times Loop executes = 200/4 = 50
(c)Total number of instructions executed = 50*9 = 450
(d)Total number of data memory for read in one iteration = 2
(e)Total number of data memory for write in one iteration = 2
(f)Total number of instruction memory in one iteration = 9
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The classic five-stage pipeline MIPS architecture is used to execute the code fragments in this problem....
The classic five-stage pipeline MIPS architecture is used to
execute the code fragments in this problem. Assume the
followings:
The architecture fully supports forwarding,
Register write is done in the first half of the clock cycle;
register read is performed in the second half of the clock
cycle,
Branches are resolved in the third stage of the pipeline and
the architecture does not utilize any branch prediction
mechanism,
Register R4 is initially 100.
L1: lw R1,
0(R4)
add R3, R1, R2
sw ...
The classic five-stage pipeline MIPS architecture is used to execute the code fragments in this problem....
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The classic five-stage pipeline MIPS architecture is used to execute the code fragments in this problem. Assume the followings: • The architecture fully supports forwarding, • Register write is done in the first half of the clock cycle; register read is performed in the second half of the clock cycle, • Branches are resolved in the third stage of the pipeline and the architecture does not utilize any branch prediction mechanism, • Register R4 is initially 200. L1: lw lw...
The classic five-stage pipeline MIPS architecture is used to
execute the code fragments in this problem. Assume the
followings:
The architecture fully supports forwarding,
Register write is done in the first half of the clock cycle;
register read is performed in the second half of the clock
cycle,
Branches are resolved in the third stage of the pipeline and
the architecture does not utilize any branch prediction
mechanism,
Register R4 is initially 100.
L1: lw R1,
0(R4)
add R3, R1, R2
sw ...
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