7(A)
The block diagram of the process is shown below
The reaction is
The number of streams
F , M, E, P, R = 5 streams
Single pass conversion = 25%
F stream analysis
Component | Kmol/h | mol% | M.W | Kg/h |
N2 | 110 | 25 | 28 | 3080 |
H2 | 330 | 75 | 2 | 660 |
Total | 440 | 100 | 3740 |
The feed ratio is stiochiometric
Ratio of H2: N2 = 3:1
95% of H2 and N2 are recycled and also 2 % of ammonia
R(x )- amount of N2 in recycle
95% of N2 in E stream is recycled
Doing N2 balance around mixer
M = 110+ R(x)
Doing N2 balance around reactor
(1-0.25)(110+ R(x))= (R(x)/0.95)
R(x)= 272.608 Kmol/h
Amount of nitrogen in recycle = 272.608 Kmol/h
Since ratio of H2: N2 = 3:1 remains constant
Amount of H2 in recycle = 272.608(3)=
817.826 kmol/h
Amount of ammonia produced according to stiochiometry in the reactor
= 2(0.25)(110+ R(x))= 2(0.25)(110+272.608)= 191.3043 Kmol/h
P analysis
Component | Kmol/h | mol% | M.W | Kg/h |
N2 | 272.608(0.05/0.95)=14.3247 | 28 | 401.0916 | |
H2 | 43.0433 | 2 | 86.086 | |
NH3 | 191.342 | 17 | 3252.822 | |
Total | 248.710 | 3740 |
Overall mass of system is conserved
Ammonia in product = 191.342 Kmol/h
98% is in product and 2% is in recycle
Ammonia in recycle = (191.342)(0.02)/0.98 = 3.9049 Kmol/h
R analysis
Component | Kmol/h | mol% |
N2 | 272.608 | 24.910 |
H2 | 817.824 | 74.732 |
NH3 | 3.9049 | 0.358 |
Total | 1094.3369 | 100 |
M analysis
Component | Kmol/h | mol% |
N2 | 272.608+110= 382.608 | 24.936 |
H2 | 817.824+ 330= 1147.824 | 74.809 |
NH3 | 3.9049 | 0.255 |
Total | 1534.3369 | 100 |
E analysis
Component | Kmol/h | mol% |
N2 | 382.608(0.75)= 286.956 | 21.428 |
H2 | 860.868 | 64.285 |
NH3 | 191.3043 | 14.287 |
Total | 1339.128 | 100 |
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