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7. A process takes hydrogen and nitrogen to make ammonia. It consists of a feed stream (Hz: 330 kmol/h and N2: 110 kmol/h), a

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Answer #1

7(A)

The block diagram of the process is shown below

The reaction is

N_{2}+ 3H_{2}\rightarrow 2NH_{3}

The number of streams

F , M, E, P, R = 5 streams

Single pass conversion = 25%

F stream analysis

Component Kmol/h mol% M.W Kg/h
N​​​​​​2 110 25 28 3080
H​​​​​​2 330 75 2 660
Total 440 100 3740

The feed ratio is stiochiometric

Ratio of H2: N2 = 3:1

95% of H2 and N2 are recycled and also 2 % of ammonia

R(x )- amount of N2 in recycle

95% of N2 in E stream is recycled

Doing N2 balance around mixer

M = 110+ R(x)

Doing N2 balance around reactor

(1-0.25)(110+ R(x))= (R(x)/0.95)

R(x)= 272.608 Kmol/h

Amount of nitrogen in recycle = 272.608 Kmol/h

Since ratio of H2: N2 = 3:1 remains constant

Amount of H2 in recycle = 272.608(3)=

817.826 kmol/h

Amount of ammonia produced according to stiochiometry in the reactor

= 2(0.25)(110+ R(x))= 2(0.25)(110+272.608)= 191.3043 Kmol/h

P analysis

Component Kmol/h mol% M.W Kg/h
N​​​​​​2 272.608(0.05/0.95)=14.3247 28 401.0916
H​​​​​​2 43.0433 2 86.086
NH​​​​​3 191.342 17 3252.822
Total 248.710 3740

Overall mass of system is conserved

Ammonia in product = 191.342 Kmol/h

98% is in product and 2% is in recycle

Ammonia in recycle = (191.342)(0.02)/0.98 = 3.9049 Kmol/h

R analysis

Component Kmol/h mol%
N​​​​​​2 272.608 24.910
H​​​​​​2 817.824 74.732
NH​​​​​3 3.9049 0.358
Total 1094.3369 100

M analysis

Component Kmol/h mol%
N​​​​​​2 272.608+110= 382.608 24.936
H​​​​​​2 817.824+ 330= 1147.824 74.809
NH​​​​​3 3.9049 0.255
Total 1534.3369 100

E analysis

Component Kmol/h mol%
N2 382.608(0.75)= 286.956 21.428
H2 860.868 64.285
NH3 191.3043 14.287
Total 1339.128 100

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