Question

The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K) 1.0 CP (kJ/kg

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Let the Polynomial be

P(x) = a_3x^3+a_2x^2+a_1x+a_0 where x = Temp, P = Cp

Now by substituting the given values we find the Constants a_3,a_2,a_1,a_0

a3 + a2 + au + do = 1.1410

a_3(1.1)^3+a_2(1.1)^2+a_1(1.1)+a_0 =1.1573

a_3(1.2)^3+a_2(1.2)^2+a_1(1.2)+a_0 =1.1722

a_3(1.3)^3+a_2(1.3)^2+a_1(1.3)+a_0 =1.1858

By solving the equations we get a = 0.0167, b = -0.125, c= 0.3703, d = 0.879

Now for Cp at T=1.45K

Cp = 0.0167(1.45)^3-0.125(1.45)^2+0.3703(1.45)+0.879 = 1.2040

For Newtons method we should Construt the differences table first.

Something similar to.

1596058369554_image.png

Then Using all the points we should construct a 6 degree polynomial(as we have 6 points).

Please Ask for any further clarifications..

Add a comment
Know the answer?
Add Answer to:
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT