Let the Polynomial be
where x = Temp, P = Cp
Now by substituting the given values we find the Constants
By solving the equations we get a = 0.0167, b = -0.125, c= 0.3703, d = 0.879
Now for Cp at T=1.45K
For Newtons method we should Construt the differences table first.
Something similar to.
Then Using all the points we should construct a 6 degree polynomial(as we have 6 points).
Please Ask for any further clarifications..
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K)...
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K) 1.0 1.1 1.2 Cp (kJ/kg.K) 1.1410 1.1573 1.1722 1.1858 1.1982 1.2095 1.3 1.4 1.5 a) Use a third order interpolation polynomial to find Cp at T = 1.45 K. Show complete solution. b) If you want to develop a model that passes through all these data points using the Newton's difference method, explain briefly without calculations how you will do it. Also, how can...
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K) 1.0 1.1 1.2 Cp (kJ/kg.K) 1.1410 1.1573 1.1722 1.1858 1.1982 1.2095 1.3 1.4 1.5 a) Use a third order interpolation polynomial to find Cp at T = 1.45 K. Show complete solution. b) If you want to develop a model that passes through all these data points using the Newton's difference method, explain briefly without calculations how you will do it. Also, how can...
numerical analysis
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K) 1.0 1.1 1.2 1.3 1.4 1.5 CP (kJ/kg.K) 1.1410 1.1573 1.1722 1.1858 1.1982 1.2095 a) Use a third order interpolation polynomial to find Cp at T = 1.45 K. Show complete solution. b) If you want to develop a model that passes through all these data points using the Newton's difference method, explain briefly without calculations how you will do it. Also,...
please answer b briefly
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K) 1.0 1.1 1.2 CP (kJ/kg.K) 1.1410 1.1573 1.1722 1.1858 1.1982 1.2095 1.3 1.4 1.5 a) Use a third order interpolation polynomial to find Cp at T = 1.45 K. Show complete solution. b) If you want to develop a model that passes through all these data points using the Newton's difference method, explain briefly without calculations how you will do...
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Abdul-Rahim Taysir
The constant-pressure specific heat of air at different temperatures are tabulated in the following table: T(K) 1.0 1.1 1.2 Cp (kJ/kg.K) 1.1410 1.1573 1.1722 1.1858 1.1982 1.2095 1.3 1.4 1.5 a) Use a third order interpolation polynomial to find Cp at T = 1.45 K. Show complete solution. b) If you want to develop a model that passes through all these data points using...
Problem 4 (hand-calculation): Consider the constant-pressure specific heat of air at high temperature presented in ta- ble 4, where T is the temperature and Cp is the specific heat. Determine a least squares quadratic polynomial approximation for this set of data. The quadratic polynomial has the following form: Cp = a + bT+cT. where the coefficients a, b and c are to be determined using the least squares method. Hint Follow the derivation of linear regression discussed in class. You...