a) µ= population mean=(1+4+7+10)/4=5.5
b)
sample | Xbar |
1 | 1 |
4 | 4 |
7 | 7 |
10 | 10 |
=============
sample | Xbar | Xbar | |
(1,4) | 2.5 | (4,7) | 5.5 |
(1,7) | 4 | (4,10) | 7 |
(1,10) | 5.5 | (7,10) | 8.5 |
============
sample | Xbar |
(1,4,7) | 4 |
(1,4,10) | 5 |
(1,7,10) | 6 |
(4,7,10) | 7 |
==========
sample | Xbar |
(1,4,7,10) | 5.5 |
c)
d)
n | Probability |
1 | 0 |
2 | 2/6 = 1/3 |
3 | 0 |
4 | 1 |
e)
n | Probability |
1 | 0 |
2 | 2/6 = 1/3 |
3 | 2/4=1/2 |
4 | 1 |
Complete parts (a) through (e) for the population data below. 1, 4, 7, 10 a. Find...
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A Data Generating Process (or population) is? (a) The sample b) The distribution that generates the data (c) The distribution of the sample mean (d) The empirical distribution of the data
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Find the sample mean x for each possible sample of size n = 2. Sample 4, 6 4, 8 4, 10 SampleX 6, 8 6, 10 8, 10 T. (Type integers or decimals rounded to two decimal places as needed.) 2