In Boolean algebra
(A + B)(A’ * B’) = ?
a) 1
b) 0
c) AB
d) AB’
Answer: Option B: 0
Explanation:
(A + B)(A’ * B’) [As per demorgan theorem (A’ * B’) = (A + B)'
= (A + B)(A + B)'
=0 [Since A.A' = 0]
Boolean Logic Reduction (Boolean Algebra) Simplify: 1+1+0= ? 11A= ? MM'1= ? X·0+1= ? C·1+DD'= ? A+0+A+0= ? A+B+1= ? 1·(E+E')= ? H+H+H+H'= ? 1·0·A= ? A+A'+B= ? A+B+A'+A·B= ? AB+CDD+BD+1= ? AA+BC+0= ? A+B+A+B+C= ? EF+0+EF'= ? B+BC= ? DE+DEF+DEG= ? ABC+A'BC+BCD= ? A'(A+B)+C= ? A+AB+A(A+B)= ? B(A+A'B)= ? A+AB+A'B+AB'+A'B'+AB= ? A'BC+AB'C+ABC= ? C(C'+AB)= ?
In Boolean logic A(A + B) = ? a) AB b) 1 c) (1 + AB) d) A
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