Based on historical data, your manager believes that 35% of the company's orders come from first-time customers. A random sample of 161 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.19?
Answer = (Enter your answer as a number accurate to 4 decimal places.)
Solution
Given that,
p = 0.35
1 - p = 1 - 0.35 = 0.65
n = 161
= p = 0.35
= [p( 1 - p ) / n] = [(0.35 * 0.65) / 161 ] = 0.0376
P( > 0.19) = 1 - P( < 0.19 )
= 1 - P(( - ) / < (0.19 - 0.35) / 0.0376)
= 1 - P(z < -4.26)
Using z table
= 1 - 0
= 1
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