a).hypothesis:-
[ as, 1-(0.60+0.05)=0.35 ]
b). the observed and expected table be:-
status | observed | test proportion | expected |
admitted unconditionally | 329 | 0.60 | 500*0.60= 300 |
trail basis | 43 | 0.05 | 500*0.05 = 25 |
refused admission | 128 | 0.35 | 500*0.35 = 175 |
sum = 500 |
c). test statistic is :-
df = (3-1) = 2
p value = 0.0000
[ in any blank cell of excel type =CHISQ.DIST.RT(28.39,2) ]
decision:-
p value = 0.0000< 0.05 (alpha)
we reject the null hypothesis. There is sufficient evidence to claim that the to date data indicate a departure from the previous admission rates.
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1) Previous enrollment records at a large university indicate that of the total number of students...
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