Question

Please, multiply the highlighted yellow digit by 6 first then solve. thank you!

Given: A4-bit adder is implemented in a carry ripple style as shown in the figure below. B3 A3 B2 A2 B1 A1 BO AO FA c3 FA FA

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Answer #1

Full adder circuit is as follows:

А. Sum INPUT full-Adder Circuit OUTPUT Carry Out B Carry In

The truth table of full adder is as follows:

Full Adder Truth table INPUTS OUTPUTS А. B Cin SUM CARRY OUT 0 0 0 0 0 0 0 1 1 0 O 1 0 1 0 1 1 0 1 1 0 1 0 O 1 0 1 0 1 1 0 0

From the truth table, we can write: Ly Sum(s) = Ā B Cin + Ā Bcin + ABCin + ABC in S = Ā[@Cin+Ban ] + a[Bein + BCin] Let Z = B

A= 0x01 and B = 0x04 -You have mentioned that this question is to be solved after multiplying A=0x01 by 6. Here a represent 0

B, A, A = 1 B=0 G=0 FA₂K CI = A,B, + C, (A, +B) = 1.0+ 0.(1+0) Si + o We got ₂ B₂ A2 A=1 B₂ = 1 C=0 C3 FARK C₂ C₂ = A₂B₂ + C₂

According to the question we need not determine the value of SUM in each case, so I haven't obtained the values of S3, S2, S1 and S0. In case you need them, you can use the expression obtained for SUM.

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