Question

Part: Part 2 of 5 Find the critical value. Round the answer to three decimal places. If there is more than one critical value, separate them with commas. The critical value(s):

Answer 1

7.

Given that,
null, H0: Ud = 0
alternate, H1: Ud < 0
level of significance, α = 0.05
from standard normal table,left tailed t α/2 =1.943
since our test is left-tailed
reject Ho, if to < -1.943
we use Test Statistic
to= d/ (S/√n)
where
value of S^2 = [ ∑ di^2 – ( ∑ di )^2 / n ] / ( n-1 ) )
d = ( Xi-Yi)/n) = -1.143
We have d = -1.143
pooled variance = calculate value of Sd= √S^2 = sqrt [ 46-(-8^2/7 ] / 6 = 2.478
to = d/ (S/√n) = -1.22
critical Value
the value of |t α| with n-1 = 6 d.f is 1.943
we got |t o| = 1.22 & |t α| =1.943
make Decision
hence Value of |to | < | t α | and here we do not reject Ho
p-value :left tail - Ha : ( p < -1.2201 ) = 0.13409
hence value of p0.05 < 0.13409,here we reject Ho
ANSWERS
---------------
a.
null, H0: Ud = 0
alternate, H1: Ud < 0
b.
test statistic: -1.22
2.
critical value: reject Ho, if to < -1.943
decision: Do not Reject Ho
p-value: 0.13409
c.
we do not have enough evidence to support the claim that the mean pain level is more with drug B.