Suppose that the time required to complete a 1040R tax form is normally distributed with a...
Suppose that the time required to complete a 1040R tax form is normally dismbited with a mean of 110 minutes and a standard denation of 20 minutes. What proportion of 1040R tax forms will be completed in at most 129 minutes? Round your answer to at least four decimal places, Answer:
D Incorrect Your answer is incorrect. Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 15 minutes. What proportion of 1040R tax forms will be completed in at most 81 minutes? Round your answer to at least four decimal places. E 0.8980 5 ?
5 6 7 8 ✓9 F 10 ✓ 11 Incorrect Your answer is incorrect. Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 15 minutes. What proportion of 1040R tax forms will be completed in at most 81 minutes? Round your answer to at least four decimal places. 0.1020 X 5 2
Answer question 1 & 2 asap please Question 1 Let Z be a standard normal random variable. Calculate the following probabilities using the calculator provided. Round your responses to at least three decimal places. ? P(Z > -1.46) P(Z < 0.63) - 0 P(-0.84 <2<2.10) - 0 Question 2 Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 20 minutes. What proportion of 1040R...
Homework 14 Question 6 of 11 (1 point) Question Attempt: 1 of Unlimited EN 5 6 7 8 - 10 11 Suppose that the time required to complete a 1040R tax form is normally distributed with a mean of 100 minutes and a standard deviation of 15 minutes. What proportion of 10400 tax forms will be completed in at most 81 minutes? Round your answer to at least four decimal places. 0
The time required for a citizen to complete the 2000 U.S. Census "long" form is normally distributed with a mean of 40 minutes and a population standard deviation of 10 minutes. What proportion of the citizens will require less than one hour?
The time required for a student to complete a Statistics exam is normally distributed with a mean of 55 minutes and a standard deviation of 12 minutes. What percent of students take between 40 and 50 minutes to complete an exam? At what point in time will 25 percent of the students have completed the exam?
The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the standard deviation of the waiting time is 2 minutes. Find the probability that a person will wait for more than 8 minutes. Round your answer the four decimal places.
The time spent waiting in the line is approximately normally distributed. The mean waiting time is 55 minutes and the standard deviation of the waiting time is 22 minutes. Find the probability that a person will wait for more than 33 minutes. Round your answer to four decimal places.
The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the standard deviation of the waiting time is 2 minutes. Find the probability that a person will wait for more than 9 minutes. Round your answer to four decimal places.