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(a) worked out incorrectly; or (b) worked out correctly but using a method not specified in the problem statement; or (c) not7) An actuarial firm budgets a new position at $36,000 for the first year and a 5% raise each year thereafter. Find the total

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Answer #1

As per the question, the compensation for the first year will be $36000

The compensation for the second year will be 5% more, that is 36000+5\%(36000)=36000(1+5\%)=36000(1+0.05)=36000(1.05)=37800

Similarly, the compensation for the 3rd year will be

37800+5\%(37800)=36000(1.05)+5\%(36000*1.05)=36000*1.05(1+5\%)=36000*(1.05)^2

.Therefore, we can write the compensation for the nth year as

36000 + (1.05)-

The total compensation across n years, will therefore be

36000+(36000*1.05)+(36000*1.05^2)+........+36000*1.05^{n-1}

As we can see, this is a geometric sum

The value of a geometric sum can be given by the formula

S_n=a(1-r^n)/(1-r), where S is the sum, a the initial term, and r the common difference.

We need to find the compensation across 20 years, so n=20

Therefore, we can write the sum as

S_{20}=36000(1-1.05^{20})/(1-1.05)

S_{20}=36000(1-2.6533)/(1-1.05)

S_{20}=36000(1.6533)/(0.05)

S_{20}=36000*33.066

S_{20}=1190376 \ dollars

Hence, the total compensation across 20 years will be 1190376 dollars

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