Question

O words Question 13 4 pts How to understand 200.23.16.0/25 in CIDR B I U A - A - I x x := TTT 12pt Paragraph 0 words

Answer 1

/25 or any /? values shows the number of 1s as here 25 1s will be there so just write in 4 octet

11111111.11111111.11111111.10000000 so total 25 1s with 4 octet now convert this binary to its equavalent decimal

255.255.255.128 will be the subnet mask and number of 0s will give us the hosts so there are 7 0s so 2^7=128 hosts will be given to use with the IP range 200.23.16.0 to 200.23.16.127.

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