Ans:-
Let X be the amount of first solution and Y be the amount of second solution.
The amount of first solution=20% of x =20x/100
The amount of second solution= 60% of y =60y/100
accordind to question.
(20x/100)+(60y/100)=40% of 80
(20x/100)+(60y/100)=(40/100)*80
20x+60y=40*80 { multiplying by 100}
x+3y=160 eq.(1)
The total amount of acid solution x+y=80 eq(2)
Therefore,
subtracting equation(1)-(2) we get,
{x+3y}-{x+y}=160-80
2y=80
y=40
from eq.(2)
x+40=80
y=40
amount of 20% acid solution (x)=40 lit.
amount of 60% acid solution (y)=40 lit.
please circle both Answers and label ______litters and 20% acid solution ___litters of 60% acid solution....