Question

Using MATLAB please.

Recall the formula for forward substitution to solve the lower triangular system 011 0 021 (122 ... 0 bi b2 0 ann be : anl an2 which is b; - ;=1 j=14; 1; i = 1,...n Write a M. "LAB function forward_substitution that solves a lower triangular system. Test your code using the example A= 2 0 0 1 1 0 2 3 b= 6 7 15 1

Answer 1

Activities MATLAB R2019b-academic use Jul 30 00:53 11 636.65 KB/S MATLAB R2019b - academic use HOME PLOTS APPS EDITOR PUBLISH VIEW E ? Search Documentation AASHISH KUMAR Workspace Name 2 Size НА 3x3 Hans 1x3 Hb 1x3 H colum lxl HI lxl lxl Hrow 1x1 1 sum lxl Шх 1x3 Ka Profiler Command History X = La Find Files Insert E. fx Run Section Compare Go To Comment % % New Open Save Breakpoints Run Run and , Advance Run and Print Q Find - Indent 1 Advance Time FILE NAVIGATE EDIT BREAKPOINTS RUN / home akm330 Downloads MATLAB Myprogram Current Folder Editor - /home/akm330/Downloads/MATLAB/Myprogram/forw... Ox Command Window Name simple.txt 2 saddleoffical.m 3 saddlel.m 4 ç function x = forword_substitution() 3.0000 4.0000 0.3333 saddle.m 5 - A=input('enter element of matrix A :'); 6 rowmax.m b=input('enter element of b:'); >> solve randi.m [row , -]=size(A); enter element of matrix A:[2 0 0;1 1 0;1 2 3] for i=l:row enter element of b:[6 7 15] Hip3.jpeg sum=0; Hi p2.jpeg 10 for j=1:1-1 Hipl.jpeg 11 sum=sum+A(i,j)*x(j); new.m 12 - end 3.0000 4.0000 1.3333 myimage.jpg 13 x(i)=(b(i) - sum)/Ali,i); multuple.m 14 end ord substitution multiplicatio... 15 - fprintf ("solution is:"); enter element of matrix A : [2 0 0;1 1 0;1 2 3] multipletable... 16 - end enter element of b:[6 7 15] multiple.m 17 solution is: minimaxl.m 18 ans = minimax.m 19 mex 20 3.0000 4.0000 1.3333 max_sum.m matlab.mat >> forword_substitution enter element of matrix A :[2 0 0;1 1 0;1 2 3] matlab enter element of b:[6 7 15] leap year.m solution is: get_distance... ans = Frankenstein... f forword_subs... 3.0000 4.0000 1.3333 familydetail.m forword_subst... A forword_substitution.m + fx >> forword_substitution Ln 3 Coll

function x = forword_substitution()
A=input('enter element of matrix A :');
b=input('enter element of b:');
[row , ~]=size(A);
for i=1:row
        sum=0;
        for j=1:i-1
            sum=sum+A(i,j)*x(j);
        end
        x(i)=(b(i)-sum)/A(i,i);
end
fprintf("solution is:");
end