Find the minimum value of n in the Balmer series for which the predicted wavelength is...
Homework Answers
λ=B*(n^2)/(n^2 - 2^2)
λ=(B*n^2) / (n^2 - 4)
λ*(n^2 -4)=B*n^2
n^2*(λ-B)=4λ
n^2=4λ/(λ-B)
n=sqrt (4λ/(λ-B))
The minimum n is for the longest ultraviolet wavelength which is
4*10^-7m=400nm
Therefore:
n=sqrt(4*4*(10^-7)/(4*(10^-7)-3.6456×(…
n=6.71913...
Therefore the minimum value of n is 7. :)
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Find the minimum value of n in the Balmer series for which the
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Use the Bohr model to find the second longest wavelength of light in the Balmer series for a triply-lonized Be atom ( Z4). Recall that the Balmer series corresponds to transitions to the n = 2 level. 30.4 nm O 117 nm 73.0 nm 41.1 nm 0 209 nm
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Use the Bohr model to find the second longest wavelength of light in the Balmer series for a doubly-ionized Li atom (Z = 3). Recall that the Balmer series corresponds to transitions to the n = 2 level. 41.1 nm 117 nm 73.0 nm 54.1 nm 209 nm
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