Question

You wish to test the following claim (H.) at a significance level of a = 0.002. H:P. 2 H.:P <P You obtain 33 successes in a sample of size 1.1 = 341 from the first population. You obtain 52 successes in a sample of size na = 398 from the second population. critical value = (three decimal accumcyl test statistic = [three decimal accuracy) The test statistic is.. in the critical region not in the critical region This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to support that the first population proportion is less than the second population proportion. There is not sufficient evidence to support that the first population proportion is less than the second population proportion.

Answer 1

Critical Value for = 2.88

Test statistic = 1.45

As the Test statistic is less than crtitical vlaue it is not in critical region.

We Accept the H_0.

final conclution is

There is not sufficient evidence to support that the first population proportion is less than the second population proportion.

Explanation:

Given that n₁ = 341, x₁=33 ; n₂= 398, x₁=52

prop1 = p₁ = 33/341 = 0.0968 ; prop2 = p₂ = 52/398 = 0.131

let the Population proportion be P

mp3 +2P2 P = ጊ + m2

85 3342 341 + 398 - = 0.115 739

Q = 1-P = 0.885

P1 P2 The test statistic is given by z = pe can this

By substituting the values we get .

Critical Value for $\alpha =0.002$ is 2.88

Please ask for further clarification.