![2 7 = 1M (2, 4,5,6,77 this function is in Pas form (as Ilm is given the no. of i/ps are 3 assuming A, B, C. Therefore, its eq](//img.homeworklib.com/questions/a5cac6a0-08c6-11eb-9fa6-f3355bb19ae8.png?x-oss-process=image/resize,w_560)
![17.00 As the Pos equation have more no of olp than the Sop equation; hence, pos would generate low Complexity oki. The Corres](//img.homeworklib.com/questions/a648ca50-08c6-11eb-8559-7391a6d285e0.png?x-oss-process=image/resize,w_560)
![00 thers; 4-7,+92 - ĀDĒ + ĀBC+Ā BD +Ā BD+ĀCĒ + A DĒ + ABC + AB 6+ ABD DE (A+Ā) + B D (A+Ā) + BD (A+Ā)+ Ā(B+ 2) + ABC = DE + B](//img.homeworklib.com/questions/a70dc200-08c6-11eb-951f-918a522757fa.png?x-oss-process=image/resize,w_560)
2 7 = 1M (2, 4,5,6,77 this function is in Pas form (as Ilm is given the no. of i/ps are 3 assuming A, B, C. Therefore, its equivalent Sop form: 4(A,B,C) -3 m (1,3) 10.30 mayo Pc
17.00 As the Pos equation have more no of olp than the Sop equation; hence, pos would generate low Complexity oki. The Corresponding ckt. is shown below, k map for Pos form. 12.30 А 6+ O+I 1+0 A 1 300 1 ( DO NCH 00 30 7- MOT A (B+C) 5) 4 = bem 2m (0,1, 4,5,6,8,10,11,12,13,14,15,16,17,18,19,20,21, 24,26,27,28,30, 31) this function is in Sop Form (as Im is given). The ho. of /ps are 5 Let us assume that A, B, C, DF E are the /ps. its equivalent Pos from, F = HTM(2,3,7,9,23,25,29) As the no. of o/p for sop is greater than Pos hence; Sop would generate low complexity ckt. As the no. of ilp is 5; the no. of k map would be 2; the Corresponding K-maps are given below, K map for A=0. (0-15) for A21 (16 31 0 Kmap DE BC 00 01 11 ot lo 1o 00 Oct - оо oji 01 o o o 10 o 101 4,-(DĒ + Be + BĐ + BD+CĒJĀ 42 - ADĒ + Be + BD+BD
00 thers; 4-7,+92 - ĀDĒ + ĀBC+Ā BD +Ā BD+ĀCĒ + A DĒ + ABC + AB 6+ ABD DE (A+Ā) + B D (A+Ā) + BD (A+Ā)+ Ā(B+ 2) + ABC = DE + B D + BD + ĀBĒ) + ABC - the Corresponding chi is shown below; A B 7 o с D E