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Consider the case of a firm that produces output x (sold at price p) using a production function x = A*/*klaße, where / is la
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Answer #1

a) A* is the productivity parameter of production function . If production technology advances , it reflects in production function as an increase in A*.

b) A production function F (x,y,z) is said to show constant returns to scale if it is homogeneous of degree 1 i.e., if all factors are increased by t units , the output also increases by t units. Let F(x,y,z) = x

F(tx, ty, tz) = t F(x,y,z)= tx

In this case production function is F(l,k,e) = A*l\alphak1-\alpha-\betae\beta

F(tl, tk,ek) = A* (tl)\alpha (tk)1-\alpha-\beta (te)\beta = t\alpha-(1-\alpha-\beta)-\betaA*l\alphak1-\alpha-\betae\beta = t F(l,k,e)

Hence the production function always show constant returns to scale ,in any conditions.

Marginal product of labour MP​​​​​L = \partial (A*l\alphak1-\alpha-\betae\beta )/\partiall = \alpha A* l\alpha-1 k1-\alpha-\betae\beta = \alpha A*l\alphak1-\alpha-\betae\beta /l = \alpha F(l,k,e)/l

If \alpha >0 the marginal product of labour decreases as more and more labour are emloyed.

If \alpha = 0 Marginal product of labour is constant = 0

If \alpha <0 Marginal product of labour is negative and increasing

Similarly , marginal product of capital = \partial (A*l\alphak1-\alpha-\betae\beta )/\partialk = (1- \alpha -\beta)A* l\alphak-\alpha-\betae\beta =(1- \alpha -\beta) A*l\alphak1-\alpha-\betae\beta /k = (1-\alpha-\beta) F(l,k,e)/k

If 1- \alpha -\beta>0 the marginal product of capital decreases as more and more labour are emloyed.

If 1- \alpha -\beta= 0 Marginal product of capital is constant = 0

If 1-\alpha-\beta<0 Marginal product of capital is negative increasing

Marginal product of energy MP​​​e = \partial (A*l\alphak1-\alpha-\betae\beta )/\partiale= \beta A* l\alphak1-\alpha-\betae\beta-1 = \beta A*l\alphak1-\alpha-\betae\beta /e= \beta F(l,k,e)/e

If \beta >0 the marginal product of energy decreases as more and more labour are emloyed.

If \beta = 0 Marginal product of energy is constant = 0

If \beta <0 Marginal product of energy is negative and increasing

c) Let us denote wages by w , cost of energy by c and cost of using capital by r

Profit = Revenue - total cost

Profit = px - ( wl - ce - rk )

Profit =  pA*l\alphak1-\alpha-\betae\beta - wl - ce - rk is the profit maximisation problem

d) Optimality condition for all inputs in the production function is derived by first order condition of profit maximisation

\partial(profit)/\partiall = 0 or \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiall - w = 0

And we know from part b that \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiall = MP​​​​​L

Therefore optimality condition for labour input is MP​​L​ = w ..

Similarly we get

\partial(profit)/\partialk = 0 or \partial ( A*l\alphak1-\alpha-\betae\beta )/\partialk - r= 0

And we know from part b that \partial ( A*l\alphak1-\alpha-\betae\beta )/\partialk= MP​​​​​K

Therefore optimality condition for capital. input is MP​​K= r

\partial(profit)/\partiale= 0 or \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiale - c= 0

And we know from part b that \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiale= MPe

Therefore optimality condition for energy input is MP​e= c

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Answer #1

a) A* is the productivity parameter of production function . If production technology advances , it reflects in production function as an increase in A*.

b) A production function F (x,y,z) is said to show constant returns to scale if it is homogeneous of degree 1 i.e., if all factors are increased by t units , the output also increases by t units. Let F(x,y,z) = x

F(tx, ty, tz) = t F(x,y,z)= tx

In this case production function is F(l,k,e) = A*l\alphak1-\alpha-\betae\beta

F(tl, tk,ek) = A* (tl)\alpha (tk)1-\alpha-\beta (te)\beta = t\alpha-(1-\alpha-\beta)-\betaA*l\alphak1-\alpha-\betae\beta = t F(l,k,e)

Hence the production function always show constant returns to scale ,in any conditions.

Marginal product of labour MP​​​​​L = \partial (A*l\alphak1-\alpha-\betae\beta )/\partiall = \alpha A* l\alpha-1 k1-\alpha-\betae\beta = \alpha A*l\alphak1-\alpha-\betae\beta /l = \alpha F(l,k,e)/l

If \alpha >0 the marginal product of labour decreases as more and more labour are emloyed.

If \alpha = 0 Marginal product of labour is constant = 0

If \alpha <0 Marginal product of labour is negative and increasing

Similarly , marginal product of capital = \partial (A*l\alphak1-\alpha-\betae\beta )/\partialk = (1- \alpha -\beta)A* l\alphak-\alpha-\betae\beta =(1- \alpha -\beta) A*l\alphak1-\alpha-\betae\beta /k = (1-\alpha-\beta) F(l,k,e)/k

If 1- \alpha -\beta>0 the marginal product of capital decreases as more and more labour are emloyed.

If 1- \alpha -\beta= 0 Marginal product of capital is constant = 0

If 1-\alpha-\beta<0 Marginal product of capital is negative increasing

Marginal product of energy MP​​​e = \partial (A*l\alphak1-\alpha-\betae\beta )/\partiale= \beta A* l\alphak1-\alpha-\betae\beta-1 = \beta A*l\alphak1-\alpha-\betae\beta /e= \beta F(l,k,e)/e

If \beta >0 the marginal product of energy decreases as more and more labour are emloyed.

If \beta = 0 Marginal product of energy is constant = 0

If \beta <0 Marginal product of energy is negative and increasing

c) Let us denote wages by w , cost of energy by c and cost of using capital by r

Profit = Revenue - total cost

Profit = px - ( wl - ce - rk )

Profit =  pA*l\alphak1-\alpha-\betae\beta - wl - ce - rk is the profit maximisation problem

d) Optimality condition for all inputs in the production function is derived by first order condition of profit maximisation

\partial(profit)/\partiall = 0 or \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiall - w = 0

And we know from part b that \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiall = MP​​​​​L

Therefore optimality condition for labour input is MP​​L​ = w ..

Similarly we get

\partial(profit)/\partialk = 0 or \partial ( A*l\alphak1-\alpha-\betae\beta )/\partialk - r= 0

And we know from part b that \partial ( A*l\alphak1-\alpha-\betae\beta )/\partialk= MP​​​​​K

Therefore optimality condition for capital. input is MP​​K= r

\partial(profit)/\partiale= 0 or \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiale - c= 0

And we know from part b that \partial ( A*l\alphak1-\alpha-\betae\beta )/\partiale= MPe

Therefore optimality condition for energy input is MP​e= c

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