Question

1. Describe how much solid NaHCO, and water you would need to create a 25.0 mL of 0.100 M NaHCO, solution. Assume the volume does not significantly change when adding the solute. Do the same for 25.0 mL of 0.100 M NaCl solution and 25.0 mL of 0.100 M KNO solution. 2. Calculate the total volume of water and of 0.4949 M NH, solution needed to create 25.0 mL of 0.100 M NH3 solution. Also calculate the total volume of water and of 0.2487 M H,SO solution needed to create 25.0 mL of 0.100 MH,SO, solution. Note: you will be using these volumes for your lab, so keep the graduated cylinders available in Beyond Labz in mind for your final answers.

Answer 1

Ans :-

[Molarity = Number of moles of solute / volume of solution in litre]

[ M = n / V ]

1 L = 1000 ml

1 ml = 1 L / 1000

[ Molarity = Given weight × 1000 / Molecular weight × Volume of solution (ml) ]

Ans .1 0.210 g NaHCO₃ is required to to create 25.0 ml of 0.100 M NaHCO₃ solution

Ans.2 0.146 g of NaCl is required to create 25.0 ml of 0.100 M solution of NaCl

6 7 Anso Given o Vml = 250ml M o. 1otora find i whacl :? By using formula- 1000 M. et of Noel Ms w M.wt Vsolution (m) : 23+ 35.5 - 58.50 5 wNach 1000 0.100= 58.5 gs- 5.85 0.1 x 58.5 x 85 Whael = ņ 1960 yo yo Whacl = 0.146g is requird. Ans. inu

Ans.3 0.252 g of KNO₃ is required to create 25.0 ml of 0.100 M KNO₃ solution.

( Anso Given. Yoni = 25.om! M so.100M find Wino = ? By using formula. M.wt. of KNO3 = 39 +14+ 3x16 1000 ME X M.wt. Vml 53 +48 lolu 40 ♡ Too : WKNO3 х 1060 98 lo! 101*0.100 X 11 WKNORE logo 4o 10.1 4 0.252g WKNO3 = 0.250g is required. Rossi