Question

BD By performing mesh analysis, calculate the assume R1 - 4Q and R2= 20) (i). the current through R1 (ii) the current through R2 and (iii) the power dissipated in the 10 Q resistor 2 A R,Ω R, Ω w w IV 3 V o 4 A 4V 10.12 312

Answer 1

RI Iz R2 . + IV 3 ②4v Elon . 12) 32 KUL loop :- -4+1+ CI+ Ig) 4 +31 = 0 I is same 4A because They are connected in series ise 'I is flowing Through 4A of Current source from loop Current Through RI = I + I3 Ij = 4A Iz = 2A [ because 'I is flowing through 2A of current source + I3 IRI = 4+2=GA IRI KUL loop @ :- -4+2 (I2 I3) + 3+ 10 12 = 0 2 Izt 1012 - 213 = 1 12 12 = 1-a13 = 1-(2x2) = -3 I2 = -3 TZ = -0.25A) Current Through R2 = I2 I3 = -0.25-2 = -2.25 A I is because of assumed direction IR2 = 2.25 A 0.625w Pion=0.6256 Pion = 12x10 = (0.25) 10.