Question

Using Mesh analysis, solve for power, in W, dissipated by R2. Vi = 3.0 V v2 = 12.0 V R1 = 4.8 ohms R2 = 1.0 ohms R3 = 8.0 ohm
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Answer #1

Given that) R2=1 Ri= 4.80 Di O I = 124 V = 30 R₂=8n + Sels Apply mesh Equation en loop KVL -R₂ 12 -V₂ R (12-1)=0 8( la W=0 -Substitute is in E qiz +12 10 iz -12.8 =3 = Voir – 14.4 12 - 19.2=3. را هاها۔ 3 +19-2 22.2 =- 5-04545A. Actual Current in Rz

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