Question

An AC generator provides power for the circuit shown below. The generator voltage is described by E(t)=Emaxsin(ωt)E(t)=Emaxsin⁡(ωt) where E=E= 120 V. Here, L=L= 640 mH, C=C= 160 μμF, R=R= 90 ΩΩ, and ω=ω= 40 rad/sec.

1)

What is the phase angle between the generator and the current?

ϕ=ϕ= -55 degrees

ϕ=ϕ= 1.1 degrees

ϕ=ϕ= 64 degrees

ϕ=ϕ= -16 degrees

ϕ=ϕ= -0.99 degrees

Your submissions:

• A

Submitted:

Wednesday, July 29 at 1:02 PM

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2)

This circuit is being driven at:

a frequency above its resonant frequency

a frequency below its resonant frequency

its resonant frequency

Your submissions:

• B

Submitted:

Wednesday, July 29 at 12:59 PM

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3)

At time t=t1t=t1, the current in the circuit is zero. What is the magnitude of the voltage across the capacitor at this time?

|VC|=|VC|= 120 V

|VC|=|VC|= 0.0048 V

|VC|=|VC|= 0.0085 V

|VC|=|VC|= 0.03 V

|VC|=|VC|= 19 V

4)

At resonance, the average power delivered by the AC generator is

〈P〉=〈P〉= 80 W

〈P〉=〈P〉= 160 W

〈P〉=〈P〉= 45.4 W

Answer 1

Resonant prequency Tic 10 [640x163x160xios = 98.82 rad sec rad/sec Here, ܐ ܘܢܬ . The circuit is driven at requency below its resonant frequency. The magnitude of the voltage across. the capacitor cobes circuit current is zero is incls 12on sonance केट 05 SU 120/2= 120/90 Les $ x 120x120 -80W