Question

Problem E: The data generated by a credit card company indicates that 40% of its clients pay their bills late. Suppose 20 clients of this company are selected at random. (23) Refer to Problem E. How many of them would you expect to pay their bill late? (1) 4 (3) 6 (4) 10 (2) 8 (24) Refer to Problem E. What is the probability that exactly 5 of them pay their bill late? --- (1) 0.126 (2) 0.051 (3) 0.075 (4) 0.177 (25) Refer to Problem E. What is the probability that more than 10 pay their bill late? (1) 0.943 (2) 0.245 (3) 0.057 (4) 0.128

Answer 1

We use the concept of Binomial Distribution here

-40 -ayo 700 b = probability that the client pay his bills late [107.in 40%. in decimals ptq=1 get-p=1-0.40 p = 0.40 = 0.60 n=20 (zu 3) E= Enfected value (or) Mean = np is= np=20x0.40= 8 option (2). use T1-84 calculator for calculations Probability that exactly's of them hay their bill late =P(5) P/8)=ny pregnar, Here res, nazo p=0.40, q=0.60 Pts)=2005 (0.405 (0.66) 20-5, 0.075 Goption() 29 Robability that more than to pay their bite late $8>10) = p (f=11) + $18=12) + plr=15)+. Hi.. plr:19) + HP (r=20) pf8>10)=2% (0.4"40-60) 72, 40-40)720-60)20-12 201960.40)*(0.00'+49 (0.00320 618710)= 0.128 (option 4) 20-11 +. +