Question

A particle of a mass 1.2 x 10 ^-11 kg and a negative charge -1.0 uC moves to the right with a speed of 3.0 x 10 ^3 m/s. It enters a uniform electric field region where the field is known to be parallel to particle's direction of motion. If the particle is to be brought to rest in the space of 4.0cm what potential difference does it have to through to stop this way and what is the strength of the field that will stop it this way

Answer 1

Mass of particle, m = 1.2x10 kg charge -1.0 ML Initial Speed, 4 = 3.0*10 m/s final speed, vo Distance, d = 4.0 cm= 0.04 m let acceleration be Using equation of motion, we have y²-u? = zad v2-42 ad - (310x103 7² 2x 0.04 1.125x108 m/s² a = - (decceleration Now, acceleration on charged particle (2) in electro field will be qE m 2 QE = 1.12 sxlo? ( magnitude B = 1125x103 x 1.2x lots lox 10-6 F 1350 N/c Now, Potential difference ove Ed Ar= 1350x 0104 Ar= 54V