Answer: Option (c) Gamma Rays
Lead is of high density and high atomic number. And lead metal preferred material for radiation shielding because lead is highly effective in providing protection from source of radiation. It is effective at stopping gamma-rays and x-rays.
2. Heavy lead shielding is necessary to protect against: a. alpha particles b. beta particles c....
Q3 List shielding materials adequate for protection from the following: a. alpha particles b. beta particles c. gamma rays E. Effect of Time on Radiation Level Time (min) 1. Counts 2. Average 3. Radiation from Background (cpm) Source (cpm) 7349 -35 7314 14904 -35(2)=-70 14834 35480 -35(3) = -105 | 35375 F. Effect of Distance on Radiation Level 1. Distance 2. Counts/min 3. Average (cm) Background (cpm) 100 77 -35 4. Radiation from Source (cpm) 55 42 117 365 330
Radon-222 Iron-59 Strontium-85 Alpha (a) Beta (6) Gamma (y) Phosphorous- emitter emitter emitter 32 (?) emitter Counts Per Counts Per Counts Per Counts Per Second (CPS) Second (CPS) P Second (CPS) Second (CPS) No shielding 280 80 40 Paper 480 200 Cardboard (1 mm) 30 40 Aluminum (1 mm) Lead Which material provides the best shielding against alpha particles? Against beta particles? Against Gamma rays? Based on the data you collected, would you say that Phosphorous-32 is an alpha, beta,...
6. Heavy charged particles are a) Alpha and beta particles b) Any particle heavier than an electron c) Charged particles heavier than an electron d) Positively charged particles heavier than a proton 7. Heavy charged particles interact through (select the best answer) a) many coulomb interactions each transferring a small fraction of the kinetic energy from the particle to target material b) a handful of coulomb collisions transferring a large fraction of their kinetic energy to the electrons in the...
1. Copper and aluminum, rather than lead, shields are used to protect against beta particle radiation because: Lead does not absorb beta particles Beta particle beams are not energetic Copper and aluminum shields scatter beta particles, as well as absorb them. Copper and aluminum shields produce less Bremsstrahlung radiation
Which of these will penetrate into lead? Select one: a. alpha particle b. beta particle c. gamma ray. d. all of the above
Look up the necessary masses and a. Show that 9Be is stable against beta decay but allowed to alpha decay b. What is the reaction for alpha decay? c. What is the energy release in this reaction? Look up the necessary masses and a. Show that 9Be is stable against beta decay but allowed to alpha decay b. What is the reaction for alpha decay? c. What is the energy release in this reaction?
Part 2: Effect of Shielding Thickness 1) Open "Experiment 3: Shielding." 2) Using Radon-222, Iron-59, and Strontium-85, determine the CPS for each nuclide with the different thicknesses of cardboard, aluminum, and lead. 3) Record your values in the data table. 4) Using your data, make two graphs, one for the B-emitter and one for the y-emitter Graph "Thickness of Shielding" vs. "Activity." Make sure to indicate proper units and label each graph with an appropriate title. Use three different lines...
When atoms of beryllium-9 are bombarded with alpha particles, the C-12 isotope is formed along with what other particle? 4 9 He+ 12c + Be - 2 4 6 neutron proton gamma particle alpha particle beta particle
19. An isotope with a high value of N/Z will end to decay through: a. alpha decay b. beta decay C. positron decay d. electron capture e. gamma decay 20.Identify the missing species in the following nuclear transmutation: 246Cm +12C 41n+? a. 254No b. 258No c. 238Cf d. 238Th e. none of the above 21. The isotope 42Sc is unstable because: a. the number of neutrons is too large in relation to the number of protons b. the number of...
1. Uranium-238 decays by a number of steps of alpha and beta decays to Lead-206. How many alpha paricles and how many beta particles are emitted? 2. Calculate the wavelength in nanometers of the blue light emitted by a mercury lamp with a frequency of 853.6 MHz. 3. Calculate the energy per mole of photons with a wavelength of 578 nm.