Question

Problem 16.01 - Enhanced - with Solution 1 of 2 Constants A coal-fired power plant that operates at an efficiency of 35 % generates 800 MW of electric power. You may want to review (Pages 499-502) Part A For related problem-solving tips and strategies, you may want view a Video Tutor Solution of Fuel consumption in a truck. How much heat does the plant discharge to the environment in one day? Express your answer to two significant figures and include the appropriate units. ВА ? Q = Value Units Submit Request Answer Provide Feedback Next >

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Answer 1

Efficiency of the plant is 35%.This means that 35% of the input power is converted into electric energy and the rest 65% is rejected .

Now, electric power generated =800 MW.

Let the input power be P.

So, 35/100*P=800

=> P=800*100/35=2285.714286 MW

So, power rejected=65/100*P=65/100*2285.714286=1485.714286 MW.

Now, energy=power*time.

Here,time=1 day=24*60*60 seconds=86400 seconds.

So, energy rejected=1485.714286*86400=128365714.3 MJ=130 TJ(tera-joules)