Question

The probability that a part produced by a certain factory's assembly line will be defective is 0.007. Find the probabilities that in a run of 40 items, the following results are obtained. (a) Exactly 3 defective items No defective items (c) At least 1 defective item a. The probability that exactly 3 parts will be defective is (Round to four decimal places as needed.) b. The probability that no parts will be defective is (Round to four decimal places as needed.) c. The probability that at least 1 part is defective is (Round to four decimal places as needed.)

Answer 1

# - 40 * 0.007 * 0.28 exactly 3 parts will be defective -dix e xl -0.28 P(x= 3) ē" (0.289 = 2.7651ai 3! Ans. adl no part will be defective: -0,28 PLX=0) = ērti 0.22 3 (0.28) O ! ē 0.22 ē 11 el 20. 7557 Aus, al at least 2 part is defections PCX31) = 1 el 0! - (-0,7557 - 0 2442/ Ane