Question

The probability that a part produced by a certain factory's assembly line will be defective is 0.012. Find the probabilities that in a run of 45 items, the following results are obtained. (a) Exactly 3 defective items (b) No defective items (c) At least 1 defective item

Answer 1

lood Le probability that about produced by a certain factory's is will be defective =p=0.012= 01012 = 3/10 The probability that about produced by a certain factoy's will be non defective =E=1-6 = 1-3/80 = 24 25 can out of 45 items, there are 3 exactly defective items non P(X= 3) = n. 63. qh-3 = 456. (3/250)? (247)48 -3 = 46(z. 3² x 24242 289)? (289) 42 15 22 P(x-3) = 45 x 89 x 43 27 x 247,92 8x2x1 (25045 - 3 15x2 43x27x (243342 (250) x (25044 25 42 38313 x (247) (250) 44 25 aby out items, of 45 tee items there is no defective plX=0)5 45Co pº -1XIX (243) PloD= P(X=0)= (247)45 250 (C) Out of 45 items, there will be at least che item will be defective Probability that catleast one item will be defective = 1-P(0)= 1-(247) 45