Question

what are 13 and 14?

Question 13 (5 points) For the following reaction: Cu(s) + Ni2+ (aq) the Eºcell for the reaction is Ni(s) + Cu2+ (aq) none of the choices 0.06 v -0.06 v 0.62 v -0.62 v Question 14 (5 points) The Eºcell For the reaction: 2 A13+ (aq) + 3 Cu(s) → 2 Al(s) + 3 Cu2+ (aq) [Cu2+] = 2.00 M and [A12+] = 0.0100 M, the Ecell for the is -2.00 V. When reaction is

Answer 1

Question 13; answer = -0.62 V

Question 14; answer= -2.048377 V

Anode E Gethode Question 13 The given reaction, Cu (S) + N2+ (aq) Ni (s) & Cu2+ (aq) Anode reaction is, Cu(s) Cu²+ (aq) + 2 e E z +0.34 v Cathode reaction is, Ni Latest 2e → Nils) -0.28 V We take the values of Eru from standard Reduction potential in water table. so. E cu 2 E Cathode - E mode 0.289 0.34 v -0.62 V (Answer) guestion 14 Theo given reaction is, 2A137 (92) + Beurs) ->2A168) + 3 Cu2+ (aq) E eu = -2.00 V and [lu 2t] = 2:00 M and [Al3+] = 0.0100m Eceu = 3. Eceu = Eren Anode reaction, 3 cu (3) 3eu?+ (aq) + be Cathode reaction, 2A13+ (aq) +6e → 2Al(s) 3eu (s) +2013+ (aq) = 364 2+ (aq) + 2 ALCs) Here, no 0.0592 we know под 9.

And = S0, бои - Eou ? [2]3 Г(2t72 Гц 2+] 3 0-0522 88 log TA (3+72 О:0592 (2-оо) 3 7-200 V Кsa Соот ор) 2- 6 1) - 2 048 377 v (fine)