A 630 Hz resonant circuit is built using a 2 mH incractor and a capacitor. What...

Question

Question

Answer 1

Answer #1

Sol::

Given::

Frequency(f)= 630 Hz
Inductance(L)= 2 mH

As the circuit is at resonance
We have
XL= XC

Where
XL=2πfL
And XC= 1/2πfC

So

2πfL= 1/2πfC
C= 1/4π²f²L
= 1/[4π²(630²)*(2*10^-3)]
= 31.92*10^-6 C
= 31.92 uC
≈ 32 uC

So third option that is 32 uC is correct.

Hope this answer helps you
Hope will get the VOTE
Thank you

Answer 2

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