Question

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3. According to government data, 25% of employed women have never been married. If 20 employed women are selected at random, what is the probability that two or fewer of them have never been married? (Note: set up a numerical expression only, but you do not have to evaluate it.) 4. Assume that the length of time between charges of a particular cell phone is normally distributed with a mean of 8 hours and a standard deviation of 2 hours. Find the probability that the cell phone will last between 5 and 10 hours between charges.

Answer 1

and n=20 p=0.25 3 Given Let o be the sample proportion. According to the questions P ( Ê £0.20) pl PC1-22 0.20-P < P(1-P) n n 0.20-0.25 20 = P(z< Voas(1-0.25) -0.05150 50.25% 0.75) = P(24 - 0.5164) =P(2_ ㄷ 0.3020 that two on Heue Thce porobabilita fever of them have never been married is 0.3028:

o 9 Kef arce x denotes the length of Couce between charges of particular cell phobl Given, xu N(02) where li o and 8=2 According to the question, p(5<x<10) = P(5-le < x-te clo-ce) 10-El =P(5-8 < 24 = P(5-9 < 24 = P(-3/<2L) =P(-1.5 LZ41) - 0.7745 Hence Ilze probabilita that the cel phone wiki last bellveen 5 andlohouss between charges Us 0.7745. 10-9

vo Let & be a continuous raudon variable with the dusiła franchica f (x2= { X ocx<4 Other coise as ? 0 Then se= E(X) = suflende Stade ă (x374 ㅗ 1) 3 64 24 11 3 Hencer la

and 02:00pm. Let a roce. & denotes the number of visitors to the information booth between 12:00 pm Here xn poisson (2) The purt of xas, x=0, 12,.. x! Given a=29 then? 2.2 ela plx-x) = 20 P(X=20) (29) =o.olas Itence the probabilitet of excelly during any given day his 0.010s. 20 visitors hour of