Question

A current of 19.0 mA is maintained in a single circular loop of 1.80 m circumference....

A current of 19.0 mA is maintained in a single circular loop of 1.80 m circumference. A magnetic field of 0.600 T is directed parallel to the plane of the loop.

(a) Calculate the magnetic moment of the loop.
mA · m2

(b) What is the magnitude of the torque exerted by the magnetic field on the loop?
mN · m

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Answer #1

and QTR = 1.8om siven, I = 19 mA, B=0.6T - R = 1.8 RT .: A = R² = (1 2 3 T =) A = 0.26 m² (0) Magnetic moment is given as- m

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