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Problem 33: Solve for Vo by using Thévenins theorem. 262 2k2 M w 0 + 12V 12mA $4k2 Zo Answer: Vo = 8 V Problem 34: Use Théve

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Answer #1

vse to Thevenins equivalent circuit : Rth RE REVO 4kn Uh is voltoge across which is voakar vi aku + Zukun ZMA vo 12V Applying kel at node vi V-12 2+ Vi-vo=0 22 2 avi-vo-12 = 2 2 2V1-Vo = 16-O vo Vo-vi FO 2 Vot 2+ vo Zoku 3kr} um 7 12V 12U Applying kel at node vi U+12 6 +4+ V-12 6 2v+-10 6 -4 2V= -24 U= - 12 V ig= V-12 6 -24 6 =-UMA Vo

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