Please solve using Norton, Ans: -2V
Please solve using Norton, Ans: -2V 4. Find Vo from following circuit using Norton's theorem only....
3. Find V, from following circuit using Thevenin's theorem. 3 kΩ 6 kΩ 3 kΩ ' 4 mA 12V 12V 4. Find Vo from following circuit using Norton's theorem only. 12V 2 ΚΩ 3 mA ( 4 ΚΩ 4 ΚΩ 12 ΚΩ
Please solve using thevenin, Ans: -12V 3. Find V, from following circuit using Thevenin's theorem. αι 3 ΚΩ 6 kΩ 3 kΩ 4 mA 12V 12 V
4. Find V, from following circuit using Norton's theorem only. 12V 2 ΚΩ 3 mA 4 ΚΩ 12 ΚΩ 4 ΚΩ
4. Find I using Norton's theorem 1 kn 1 kΩ V + 2V 2 k2 12 V Answer: = 4mA 5. Use Thèvenin's theorem to find Va. 1000 6 kn 1 kn + 2 kΩS 2 kΩ 3 V 1 mA V Answer: V = V 6, Use Norton's theorem to find V Š1 k2 4000 2 kn 3 kn V3 kn 1 mA Answer: V= =1.4516V 4. Find I using Norton's theorem 1 kn 1 kΩ V + 2V...
Find V, from following circuit using Thevenin's theorem. 3 ΚΩ 6 kΩ 3 kΩ 4 mA 12V 12 V
Please solve again, these are WRONG. Be thorough please. Use Norton's theorem to find Io in the circuit in the figure below. Break the network at the 2k Ohm resistor containing Io. 3 Ν 8 kΩ 5 kΩ 3 mA 5 mA 8 kg 2 ΚΩ
3. Find V, from following circuit using Thevenin's theorem. 3 kΩ 6 kΩ: 3 kΩ 4 mA 12V ) 12V
find I using Norton's theorem, please show all work. 1. Find I, using Norton's theorem. 12 V 12v • 34612 {6kn Doma
Use mesh analysis to find Vo in the circuit below. 6 mA + V. - 6 ΚΩ Τ 12v Β) 12 ΚΩ Ι 12 kΩ ΚΑΙ 2 mA T
Find V. in the circuit in the figure below using superposition. =3 mA 7 kΩ Ο 4 kg 7 kΩ Ta = 2V I h = 8V 4 ΚΩ 6 kΩ Ι ο Vo with only V, turned on Vo with only V6 turned on 75.6 V with only I, on = V =