Question

Please solve again, these are WRONG. Be thorough please.

Use Norton's theorem to find Io in the circuit in the figure below. Break the network at the 2k Ohm resistor containing Io. 3 Ν 8 kΩ 5 kΩ 3 mA 5 mA 8 kg 2 ΚΩ

Answer 1

av {ska KU 3mm Ska? S26.2 V1 first renove 13 aur ston's across AB terminale Equinalent resistance across AB termials boy deactivating independant sources. Vollage source=short circuited clisment source = open circuited. Skillsk = 4ks 2 A م هه 3 skr. Rw = 4k|(51 . They see kur Firuz 2.999kn skins مع کے ج- Step Bye short circuit AB - terminals & find In current circuit can be redrawn as A . لے 1 m. Esk av ☺ T SMA 8km

vollege-o By source transformation Current Source Can be converted into voltage source LOB You V=IR . 5546624846-3 =yor. B . T = 40-30 i. Fu = It 3mA = 37+8= 7,625mA Step 3: fincling Is, from Noston's Equivalent. tit. Fan 71625 to 3X3 7.625 by cenfent division nur To = 7,625 X6 3 x 20 xo? tajutes x103A. To= 4.01315 Io = 4.01315 MA. -
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